What is the answer to log_{2}(12-2^x)=2x ?

The answer to log_{2}(12-2^x)=2x is x=(ln(3))/(ln(2))

Solve for x: log_{2}(12-2^x)=2x

The solution is x=(ln(3))/(ln(2))

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lo g_{2} (12 - 2^{x}) = 2 x

x = \frac{ln ( 3 )}{ln ( 2 )}

Solution steps

lo g_{2} (12 - 2^{x}) = 2 x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (12 - 2^{x})} = 2^{2 x}

Simplify

2^{l o g_{2} (12 - 2^{x})} : 12 - 2^{x}

Simplify

2^{2 x} : 4^{x}

12 - 2^{x} = 4^{x}

Solve

12 - 2^{x} = 4^{x} : x = \frac{ln ( 3 )}{ln ( 2 )}

x = \frac{ln ( 3 )}{ln ( 2 )}

Verify Solutions:

x = \frac{ln ( 3 )}{ln ( 2 )}

True

The solution is

x = \frac{ln ( 3 )}{ln ( 2 )}

x^{l o g_{4} (x^{9})} = (4 x)^{12}

ln (x) = - \frac{4 x}{e} + 5

62 = 10 lo g_{10} (\frac{x}{85})

0.501 = lo g_{10} (x)

lo g_{2 x} (x) = - 2

What is the answer to log_{2}(12-2^x)=2x ?
The answer to log_{2}(12-2^x)=2x is x=(ln(3))/(ln(2))
Solve for x: log_{2}(12-2^x)=2x
The solution is x=(ln(3))/(ln(2))