What are the solutions to the equation 3x^2+6x+5=0 ?

The solutions to the equation 3x^2+6x+5=0 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)

Find the zeros of 3x^2+6x+5=0

The zeros of 3x^2+6x+5=0 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)

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3 x^{2} + 6 x + 5 = 0

x = - 1 + i \frac{2}{3}, x = - 1 - i \frac{2}{3}

Solution steps

3 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 5 : 26 i

x_{1, 2} = \frac{- 6 \pm 2 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 6 i}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 6 i}{2 \cdot 3}

x = \frac{- 6 + 2 6 i}{2 \cdot 3} : - 1 + i \frac{2}{3}

x = \frac{- 6 - 2 6 i}{2 \cdot 3} : - 1 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{2}{3}, x = - 1 - i \frac{2}{3}

(x + 7) (x - 10) = 1

(1 - 7 i)^{2}

∣ 2 x - 3 ∣ - 4 \leq 5

∣ - 4 + 7 ∣

\frac{2}{5} - \frac{1}{10}

What are the solutions to the equation 3x^2+6x+5=0 ?
The solutions to the equation 3x^2+6x+5=0 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)
Find the zeros of 3x^2+6x+5=0
The zeros of 3x^2+6x+5=0 are x=-1+isqrt(2/3),x=-1-isqrt(2/3)