What is the answer to log_{10}(1/x)=7.22 ?

The answer to log_{10}(1/x)=7.22 is x= 1/(10^{7.22)}

Solve for x: log_{10}(1/x)=7.22

The solution is x= 1/(10^{7.22)}

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lo g_{10} (\frac{1}{x}) = 7.22

x = \frac{1}{1 0 ^{7.22}}

Solution steps

lo g_{10} (\frac{1}{x}) = 7.22

Apply log rules

\frac{1}{x} = 1 0^{7.22}

Multiply both sides by

x

\frac{1}{x} x = 1 0^{7.22} x

Simplify

1 = 1 0^{7.22} x

Solve

1 = 1 0^{7.22} x : x = \frac{1}{1 0 ^{7.22}}

x = \frac{1}{1 0 ^{7.22}}

Verify Solutions:

x = \frac{1}{1 0 ^{7.22}}

True

The solution is

x = \frac{1}{1 0 ^{7.22}}

5 lo g_{4} (x - 2) - 16 = - 16

lo g_{10} (\frac{1}{x}) = 7.87

x, 0.67 = lo g_{10} (x)

(ln (x))^{2} = 3 ln (x) - 2

lo g_{3} (x) + lo g_{27} (x) = 16

What is the answer to log_{10}(1/x)=7.22 ?
The answer to log_{10}(1/x)=7.22 is x= 1/(10^{7.22)}
Solve for x: log_{10}(1/x)=7.22
The solution is x= 1/(10^{7.22)}