What is the answer to b=6-2.5log_{4.53}(x) ?

The answer to b=6-2.5log_{4.53}(x) is x=4.53^{-(2(b-6))/5}

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b=6-2.5log_{4.53}(x)

b = 6 - 2.5 lo g_{4.53} (x)

x = 4.5 3^{- \frac{2 ( b - 6 )}{5}}

Solution steps

b = 6 - 2.5 lo g_{4.53} (x)

Switch sides

6 - 2.5 lo g_{4.53} (x) = b

Multiply both sides by

10

60 - 25 lo g_{4.53} (x) = b \cdot 10

Move

60

to the right side

- 25 lo g_{4.53} (x) = b \cdot 10 - 60

Divide both sides by

- 25

lo g_{4.53} (x) = - \frac{2 ( b - 6 )}{5}

Apply log rules

x = 4.5 3^{- \frac{2 ( b - 6 )}{5}}

Verify Solutions:

x = 4.5 3^{- \frac{2 ( b - 6 )}{5}}

True

The solution is

x = 4.5 3^{- \frac{2 ( b - 6 )}{5}}

lo g_{b} (2) = 1.73

ln (x + 4) = 2 ln (x) + ln (4)

x^{(l o g_{10} (x))} = 100 x

ln (x) = 5.297293, x

lo g_{10} (x^{2}) = 10

What is the answer to b=6-2.5log_{4.53}(x) ?
The answer to b=6-2.5log_{4.53}(x) is x=4.53^{-(2(b-6))/5}