What is the answer to log_{2}(x-2)=log_{4}(2x+4) ?

The answer to log_{2}(x-2)=log_{4}(2x+4) is x=6

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log_{2}(x-2)=log_{4}(2x+4)

lo g_{2} (x - 2) = lo g_{4} (2 x + 4)

x = 6

Solution steps

lo g_{2} (x - 2) = lo g_{4} (2 x + 4)

Apply log rules

(x - 2)^{2} = 2 x + 4

Solve

(x - 2)^{2} = 2 x + 4 : x = 6, x = 0

x = 6, x = 0

Verify Solutions:

x = 6

True

, x = 0

False

The solution is

x = 6

lo g_{e} (x - 4) = 5

lo g_{2} (9) = 2 lo g_{2} (x)

ln (x^{4} - 5 x^{2} + 4) = - 1

lo g_{2} (x + 4) = - lo g_{2} (x + 7) + 2

ln (3 x - 17) = 4

What is the answer to log_{2}(x-2)=log_{4}(2x+4) ?
The answer to log_{2}(x-2)=log_{4}(2x+4) is x=6
Solve for x: log_{2}(x-2)=log_{4}(2x+4)
The solution is x=6