What is the answer to x=ln(x-1)-ln(4) ?

The answer to x=ln(x-1)-ln(4) is No Solution for x\in\mathbb{R}

Solve for x: x=ln(x-1)-ln(4)

The solution is No Solution for x\in\mathbb{R}

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x = ln (x - 1) - ln (4)

No Solution for x \in R

Solution steps

x = ln (x - 1) - ln (4)

Switch sides

ln (x - 1) - ln (4) = x

Move

ln (4)

to the right side

ln (x - 1) = x + ln (4)

Apply log rules

ln (x - 1) = x + 2 ln (2)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x - 1)} = e^{x + 2 l n (2)}

Simplify

e^{l n (x - 1)} : x - 1

Simplify

e^{x + 2 l n (2)} : 4 e^{x}

x - 1 = 4 e^{x}

Solve

x - 1 = 4 e^{x} :

No Solution for

x \in R

No Solution for x \in R

lo g_{5} (x - 1) = 2

ln (x + 3) - ln (x - 1) = ln (3)

lo g_{10} (5 x + 2) = lo g_{10} (x - 3)

ln (u - 10) = ln (8)

- lo g_{10} (x) = 14.8

What is the answer to x=ln(x-1)-ln(4) ?
The answer to x=ln(x-1)-ln(4) is No Solution for x\in\mathbb{R}
Solve for x: x=ln(x-1)-ln(4)
The solution is No Solution for x\in\mathbb{R}