What is the answer to ln(x+2)-ln(x)=4 ?

The answer to ln(x+2)-ln(x)=4 is x= 2/(e^4-1)

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ln(x+2)-ln(x)=4

ln (x + 2) - ln (x) = 4

x = \frac{2}{e ^{4} - 1}

Solution steps

ln (x + 2) - ln (x) = 4

Add

ln (x)

to both sides

ln (x + 2) - ln (x) + ln (x) = 4 + ln (x)

Simplify

ln (x + 2) = 4 + ln (x)

Apply log rules

x + 2 = e^{4} x

Solve

x + 2 = e^{4} x : x = \frac{2}{e ^{4} - 1}

x = \frac{2}{e ^{4} - 1}

Verify Solutions:

x = \frac{2}{e ^{4} - 1}

True

The solution is

x = \frac{2}{e ^{4} - 1}

lo g_{a} (a) = 2

lo g_{y} (2) = 8

ln (x + 1) - ln (x - 5) = 3

0 = - \frac{ln ( - 3 ( 0 ) ^{2} + c )}{2}

lo g_{5} (2 (x^{3} + 5)) = 2

What is the answer to ln(x+2)-ln(x)=4 ?
The answer to ln(x+2)-ln(x)=4 is x= 2/(e^4-1)
Solve for x: ln(x+2)-ln(x)=4
The solution is x= 2/(e^4-1)