What are the solutions to the equation 16x^2-8x=-1 ?

The solutions to the equation 16x^2-8x=-1 are x= 1/4

Find the zeros of 16x^2-8x=-1

The zeros of 16x^2-8x=-1 are x= 1/4

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16 x^{2} - 8 x = - 1

x = \frac{1}{4}

Solution steps

16 x^{2} - 8 x = - 1

Move

1

to the left side

16 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 \cdot 1}{2 \cdot 16}

(- 8)^{2} - 4 \cdot 16 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 8 )}{2 \cdot 16}

\frac{- ( - 8 )}{2 \cdot 16} = \frac{1}{4}

x = \frac{1}{4}

The solution to the quadratic equation is:

x = \frac{1}{4}

3^{2} + 5^{2} = c^{2}

\frac{4}{x} + \frac{10}{y}

\frac{1}{3 6 ^{- \frac{1}{2}}}

\frac{2}{4 + 5}

5 - 5 i

What are the solutions to the equation 16x^2-8x=-1 ?
The solutions to the equation 16x^2-8x=-1 are x= 1/4
Find the zeros of 16x^2-8x=-1
The zeros of 16x^2-8x=-1 are x= 1/4