What is the answer to log_{2}(x-5)-log_{2}(x+5)=5 ?

The answer to log_{2}(x-5)-log_{2}(x+5)=5 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(x-5)-log_{2}(x+5)=5

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (x - 5) - lo g_{2} (x + 5) = 5

No Solution for x \in R

Solution steps

lo g_{2} (x - 5) - lo g_{2} (x + 5) = 5

Add

lo g_{2} (x + 5)

to both sides

lo g_{2} (x - 5) - lo g_{2} (x + 5) + lo g_{2} (x + 5) = 5 + lo g_{2} (x + 5)

Simplify

lo g_{2} (x - 5) = 5 + lo g_{2} (x + 5)

Apply log rules

x - 5 = 32 (x + 5)

Solve

x - 5 = 32 (x + 5) : x = - \frac{165}{31}

x = - \frac{165}{31}

Verify Solutions:

x = - \frac{165}{31}

False

The solution is

No Solution for x \in R

lo g_{10} (2 - x) = 3

- ln (x - 1) = 2

2 lo g_{3} (x + 4) = lo g_{3} (9) + 2

lo g_{5} (x + 1) = 12

lo g_{5} (x) - lo g_{5} (14) = 3

What is the answer to log_{2}(x-5)-log_{2}(x+5)=5 ?
The answer to log_{2}(x-5)-log_{2}(x+5)=5 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(x-5)-log_{2}(x+5)=5
The solution is No Solution for x\in\mathbb{R}