What is the answer to log_{10}(2)(log_{3}(x))=-1 ?

The answer to log_{10}(2)(log_{3}(x))=-1 is x= 1/(3^{\frac{1){log_{10}(2)}}}

Solve for x: log_{10}(2)(log_{3}(x))=-1

The solution is x= 1/(3^{\frac{1){log_{10}(2)}}}

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lo g_{10} (2) (lo g_{3} (x)) = - 1

x = \frac{1}{3 ^{\frac{1}{l o g _{10} ( 2 )}}}

Solution steps

lo g_{10} (2) (lo g_{3} (x)) = - 1

Divide both sides by

lo g_{10} (2)

lo g_{3} (x) = - \frac{1}{lo g _{10} ( 2 )}

Apply log rules

x = \frac{1}{3 ^{\frac{1}{l o g _{10} ( 2 )}}}

Verify Solutions:

x = \frac{1}{3 ^{\frac{1}{l o g _{10} ( 2 )}}}

True

The solution is

x = \frac{1}{3 ^{\frac{1}{l o g _{10} ( 2 )}}}

2 lo g_{10} (x) - 3 = 5

x, lo g_{9} (x) = 2

lo g_{b} (1) = 1

lo g_{6} (x^{2}) 2 lo g_{6} (x) = 1

0 = lo g_{2} (5 - x)

What is the answer to log_{10}(2)(log_{3}(x))=-1 ?
The answer to log_{10}(2)(log_{3}(x))=-1 is x= 1/(3^{\frac{1){log_{10}(2)}}}
Solve for x: log_{10}(2)(log_{3}(x))=-1
The solution is x= 1/(3^{\frac{1){log_{10}(2)}}}