What is the answer to log_{4}(x+2)+log_{4}(x-4)=2 ?

The answer to log_{4}(x+2)+log_{4}(x-4)=2 is x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(x+2)+log_{4}(x-4)=2

lo g_{4} (x + 2) + lo g_{4} (x - 4) = 2

x = 6

Solution steps

lo g_{4} (x + 2) + lo g_{4} (x - 4) = 2

Apply log rules

(x + 2) (x - 4) = 16

Solve

(x + 2) (x - 4) = 16 : x = 6, x = - 4

x = 6, x = - 4

Verify Solutions:

x = 6

True

, x = - 4

False

The solution is

x = 6

ln (4 x) + 1 = 0

lo g_{y} (125) = - \frac{3}{2}

lo g_{2} (x) + lo g_{x} (4) = 3

7 - 2 ln (x) = 2

H, p = - lo g_{10} (H)

What is the answer to log_{4}(x+2)+log_{4}(x-4)=2 ?
The answer to log_{4}(x+2)+log_{4}(x-4)=2 is x=6
Solve for x: log_{4}(x+2)+log_{4}(x-4)=2
The solution is x=6