What is the answer to log_{4}(3x+4)+log_{4}(16)=5 ?

The answer to log_{4}(3x+4)+log_{4}(16)=5 is x=20

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log_{4}(3x+4)+log_{4}(16)=5

lo g_{4} (3 x + 4) + lo g_{4} (16) = 5

x = 20

Solution steps

lo g_{4} (3 x + 4) + lo g_{4} (16) = 5

Move

lo g_{4} (16)

to the right side

lo g_{4} (3 x + 4) = 5 - lo g_{4} (16)

Apply log rules

3 x + 4 = 64

Solve

3 x + 4 = 64 : x = 20

x = 20

Verify Solutions:

x = 20

True

The solution is

x = 20

lo g_{6} (x + 6) = 2

13.8 = - 0.008315 (310.15) ln (x)

lo g_{10} (8 x) = - 2

n (x) = lo g_{\frac{2}{e}} (x)

ln (x) = \frac{90}{10}

What is the answer to log_{4}(3x+4)+log_{4}(16)=5 ?
The answer to log_{4}(3x+4)+log_{4}(16)=5 is x=20
Solve for x: log_{4}(3x+4)+log_{4}(16)=5
The solution is x=20