What is the answer to 16=-log_{10}(x) ?

The answer to 16=-log_{10}(x) is x= 1/(10^{16)}

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16=-log_{10}(x)

16 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{16}}

Solution steps

16 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

16 + lo g_{10} (x) = 0

Move

16

to the right side

lo g_{10} (x) = - 16

Apply log rules

x = \frac{1}{1 0 ^{16}}

Verify Solutions:

x = \frac{1}{1 0 ^{16}}

True

The solution is

x = \frac{1}{1 0 ^{16}}

4 ln (6 x) = 12

lo g_{4} (3 x + 4) = 3

lo g_{4} (3 x + 4) = 2

y, ln (y) = 9 t + 5

y, ln (y) = 6 ln (x) + c

What is the answer to 16=-log_{10}(x) ?
The answer to 16=-log_{10}(x) is x= 1/(10^{16)}
Solve for x: 16=-log_{10}(x)
The solution is x= 1/(10^{16)}