What is the answer to log_{5}(x+5)+log_{5}(x-4)=3 ?

The answer to log_{5}(x+5)+log_{5}(x-4)=3 is x=(-1+sqrt(581))/2

Solve for x: log_{5}(x+5)+log_{5}(x-4)=3

The solution is x=(-1+sqrt(581))/2

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lo g_{5} (x + 5) + lo g_{5} (x - 4) = 3

x = \frac{- 1 + 581}{2}

Solution steps

lo g_{5} (x + 5) + lo g_{5} (x - 4) = 3

Apply log rules

(x + 5) (x - 4) = 125

Solve

(x + 5) (x - 4) = 125 : x = \frac{- 1 + 581}{2}, x = \frac{- 1 - 581}{2}

x = \frac{- 1 + 581}{2}, x = \frac{- 1 - 581}{2}

Verify Solutions:

x = \frac{- 1 + 581}{2}

True

, x = \frac{- 1 - 581}{2}

False

The solution is

x = \frac{- 1 + 581}{2}

lo g_{3} (x) = x

lo g_{3} (x) = a

x, y - ln (x + 1) = 0

ln (2) + ln (x - 4) = ln (x)

6 + 5 ln (4 x - 3) = 2

What is the answer to log_{5}(x+5)+log_{5}(x-4)=3 ?
The answer to log_{5}(x+5)+log_{5}(x-4)=3 is x=(-1+sqrt(581))/2
Solve for x: log_{5}(x+5)+log_{5}(x-4)=3
The solution is x=(-1+sqrt(581))/2