What is the answer to 3.2=-log_{10}(x) ?

The answer to 3.2=-log_{10}(x) is x= 1/(10^{3.2)}

Solve for x: 3.2=-log_{10}(x)

The solution is x= 1/(10^{3.2)}

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3.2 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{3.2}}

Solution steps

3.2 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

3.2 + lo g_{10} (x) = 0

Move

3.2

to the right side

lo g_{10} (x) = - 3.2

Apply log rules

x = \frac{1}{1 0 ^{3.2}}

Verify Solutions:

x = \frac{1}{1 0 ^{3.2}}

True

The solution is

x = \frac{1}{1 0 ^{3.2}}

lo g_{10} (x) = - 4.1

6 ln (2 x + 10) - 4 = 8

lo g_{4} (x) = \frac{- 1}{2}

0.7 = ln (y)

x, 4 ln (x + 6) = - 4

What is the answer to 3.2=-log_{10}(x) ?
The answer to 3.2=-log_{10}(x) is x= 1/(10^{3.2)}
Solve for x: 3.2=-log_{10}(x)
The solution is x= 1/(10^{3.2)}