What is the answer to log_{10}(x-2)=1.258 ?

The answer to log_{10}(x-2)=1.258 is x=10^{1.258}+2

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log_{10}(x-2)=1.258

lo g_{10} (x - 2) = 1.258

x = 1 0^{1.258} + 2

Solution steps

lo g_{10} (x - 2) = 1.258

Apply log rules

x - 2 = 1 0^{1.258}

Solve

x - 2 = 1 0^{1.258} : x = 1 0^{1.258} + 2

x = 1 0^{1.258} + 2

ln (x) = ln (2 x - 3)

lo g_{7} (10 x) + 20 = 0

lo g_{3} (x) = 2.2

lo g_{10} (x) = 0.7929 - 1

0 = lo g_{3} (x)

What is the answer to log_{10}(x-2)=1.258 ?
The answer to log_{10}(x-2)=1.258 is x=10^{1.258}+2
Solve for x: log_{10}(x-2)=1.258
The solution is x=10^{1.258}+2