What is the answer to ln(x+1)*sqrt(2x+1)=0 ?

The answer to ln(x+1)*sqrt(2x+1)=0 is x=0,x=-1/2

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ln(x+1)*sqrt(2x+1)=0

ln (x + 1) \cdot 2 x + 1 = 0

x = 0, x = - \frac{1}{2}

Solution steps

ln (x + 1) 2 x + 1 = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

ln (x + 1) = 0 or 2 x + 1 = 0

Solve

ln (x + 1) = 0 : x = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Verify Solutions:

x = 0

True

, x = - \frac{1}{2}

True

The solutions are

x = 0, x = - \frac{1}{2}

lo g_{x} (\frac{8}{27}) = 3

ln (3 x + e) = 5

ln (x^{8}) - ln (x^{4}) = 4

ln (3 x + e) = 9

lo g_{10} (7 x) = 1

What is the answer to ln(x+1)*sqrt(2x+1)=0 ?
The answer to ln(x+1)*sqrt(2x+1)=0 is x=0,x=-1/2
Solve for x: ln(x+1)*sqrt(2x+1)=0
The solution is x=0,x=-1/2