What is the answer to 1+log_{10}(3x-4)=0 ?

The answer to 1+log_{10}(3x-4)=0 is x= 41/30

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1+log_{10}(3x-4)=0

1 + lo g_{10} (3 x - 4) = 0

x = \frac{41}{30}

Solution steps

1 + lo g_{10} (3 x - 4) = 0

Move

1

to the right side

lo g_{10} (3 x - 4) = - 1

Apply log rules

3 x - 4 = \frac{1}{10}

Solve

3 x - 4 = \frac{1}{10} : x = \frac{41}{30}

x = \frac{41}{30}

Verify Solutions:

x = \frac{41}{30}

True

The solution is

x = \frac{41}{30}

ln (x^{5}) - ln (x^{3}) - 4 = 0

2 = lo g_{10} (\frac{1}{x})

lo g_{3} (9 x) + 3 lo g_{3} (4) = 0

lo g_{7} (3 x + 2) = lo g_{7} (2 x + 5)

ln (k) = 6.788

What is the answer to 1+log_{10}(3x-4)=0 ?
The answer to 1+log_{10}(3x-4)=0 is x= 41/30
Solve for x: 1+log_{10}(3x-4)=0
The solution is x= 41/30