What is the answer to log_{10}(1/(1-x))=-1 ?

The answer to log_{10}(1/(1-x))=-1 is x=-9

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log_{10}(1/(1-x))=-1

lo g_{10} (\frac{1}{1 - x}) = - 1

x = - 9

Solution steps

lo g_{10} (\frac{1}{1 - x}) = - 1

Apply log rules

\frac{1}{1 - x} = 1 0^{- 1}

Multiply both sides by

1 - x

\frac{1}{1 - x} (1 - x) = 1 0^{- 1} (1 - x)

Simplify

1 0^{- 1} (1 - x) : \frac{1}{10} (1 - x)

1 = \frac{1}{10} (1 - x)

Solve

1 = \frac{1}{10} (1 - x) : x = - 9

x = - 9

Verify Solutions:

x = - 9

True

The solution is

x = - 9

2 x - 2 + ln (x) = 0

2 lo g_{10} (x) = - 1

- 2 = lo g_{\frac{2}{3}} (x - 2)

4 lo g_{8} (x) = lo g_{8} (x^{n})

lo g_{x} (1) = 4

What is the answer to log_{10}(1/(1-x))=-1 ?
The answer to log_{10}(1/(1-x))=-1 is x=-9
Solve for x: log_{10}(1/(1-x))=-1
The solution is x=-9