What is the answer to solvefor x,ln(y)=ln(x+1) ?

The answer to solvefor x,ln(y)=ln(x+1) is x=y-1 {y>0}

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solvefor x,ln(y)=ln(x+1)

solve for

x, ln (y) = ln (x + 1)

x = y - 1 {y > 0}

Solution steps

ln (y) = ln (x + 1)

Apply log rules

y = x + 1

Solve

y = x + 1 : x = y - 1

x = y - 1

Verify Solutions:

x = y - 1 {y > 0}

The solution is

x = y - 1 {y > 0}

x = 1 + 3.322 (lo g_{28} (x))

lo g_{10} (x) = 1.97 - 1.32

x, ln (y) = ln (x + 2)

lo g_{5} (a + 3) = 1 - lo g_{5} (a - 1)

50 = 10 lo g_{10} (x)

What is the answer to solvefor x,ln(y)=ln(x+1) ?
The answer to solvefor x,ln(y)=ln(x+1) is x=y-1 {y>0}