What is the answer to log_{10}(b)81=-4 ?

The answer to log_{10}(b)81=-4 is b= 1/(10^{4/81)}

Solve for b: log_{10}(b)81=-4

The solution is b= 1/(10^{4/81)}

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lo g_{10} (b) 81 = - 4

b = \frac{1}{1 0 ^{\frac{4}{81}}}

Decimal Notation

b = 0.89251 \dots

Solution steps

lo g_{10} (b) \cdot 81 = - 4

Divide both sides by

81

lo g_{10} (b) = - \frac{4}{81}

Apply log rules

b = \frac{1}{1 0 ^{\frac{4}{81}}}

Verify Solutions:

b = \frac{1}{1 0 ^{\frac{4}{81}}}

True

The solution is

b = \frac{1}{1 0 ^{\frac{4}{81}}}

0 = ln (x) + ln (2 - x)

7 = lo g_{5} (M)

3 lo g_{4} (4) = lo g_{4} (x)

4 ln (6 x + 2) - 16 = 16

lo g_{4} (x + 2) - lo g_{4} (x - 1) = 0

What is the answer to log_{10}(b)81=-4 ?
The answer to log_{10}(b)81=-4 is b= 1/(10^{4/81)}
Solve for b: log_{10}(b)81=-4
The solution is b= 1/(10^{4/81)}