What is the answer to ln(3t+1)-ln(2t+3)=0 ?

The answer to ln(3t+1)-ln(2t+3)=0 is t=2

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ln(3t+1)-ln(2t+3)=0

ln (3 t + 1) - ln (2 t + 3) = 0

t = 2

Solution steps

ln (3 t + 1) - ln (2 t + 3) = 0

Add

ln (2 t + 3)

to both sides

ln (3 t + 1) - ln (2 t + 3) + ln (2 t + 3) = 0 + ln (2 t + 3)

Simplify

ln (3 t + 1) = ln (2 t + 3)

Apply log rules

3 t + 1 = 2 t + 3

Solve

3 t + 1 = 2 t + 3 : t = 2

t = 2

Verify Solutions:

t = 2

True

The solution is

t = 2

lo g_{3} (3 x - 12) - lo g_{3} (x) = 2

lo g_{10} (x) = 2.983

lo g_{6} (8 x) - 4 lo g_{6} (2) = 0

ln (3 x - 13) = 8

ln (3 x - 13) = 9

What is the answer to ln(3t+1)-ln(2t+3)=0 ?
The answer to ln(3t+1)-ln(2t+3)=0 is t=2
Solve for t: ln(3t+1)-ln(2t+3)=0
The solution is t=2