What is the answer to log_{10}(x)=2.952 ?

The answer to log_{10}(x)=2.952 is x=10^{2.952}

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log_{10}(x)=2.952

lo g_{10} (x) = 2.952

x = 1 0^{2.952}

Decimal Notation

x = 895.36476 \dots

Solution steps

lo g_{10} (x) = 2.952

Apply log rules

x = 1 0^{2.952}

15 = 10 lo g_{10} (x)

2 ln (x) = ln (x^{4}) - ln (8)

lo g_{4} (x) = 1.5

ln (x + 1) = 4

lo g_{2} (5 x) - 3 lo g_{2} (7) = 0

What is the answer to log_{10}(x)=2.952 ?
The answer to log_{10}(x)=2.952 is x=10^{2.952}
Solve for x: log_{10}(x)=2.952
The solution is x=10^{2.952}