What is the answer to log_{4}(x)+log_{2}(x)=12 ?

The answer to log_{4}(x)+log_{2}(x)=12 is x=256

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log_{4}(x)+log_{2}(x)=12

lo g_{4} (x) + lo g_{2} (x) = 12

x = 256

Solution steps

lo g_{4} (x) + lo g_{2} (x) = 12

Apply log rules

x = 256

Verify Solutions:

x = 256

True

The solution is

x = 256

lo g_{10} (x) = - 2.9

lo g_{10} (x) = - 2.8

lo g_{10} (E) = 11.8 + 1.5 (7)

\frac{x}{lo g _{10} ( x )} = 4

x, ln (y) = ln (x) - x

What is the answer to log_{4}(x)+log_{2}(x)=12 ?
The answer to log_{4}(x)+log_{2}(x)=12 is x=256
Solve for x: log_{4}(x)+log_{2}(x)=12
The solution is x=256