What is 1+(2x)/7-1/2 (x+7)>= x ?

The solution to 1+(2x)/7-1/2 (x+7)>= x is x<=-35/17

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1+(2x)/7-1/2 (x+7)>= x

1 + \frac{2 x}{7} - \frac{1}{2} (x + 7) \geq x

x \leq - \frac{35}{17}

Interval Notation

(- \infty, - \frac{35}{17}]

Decimal Notation

x \leq - 2.05882 \dots

Solution steps

1 + \frac{2 x}{7} - \frac{1}{2} (x + 7) \geq x

Move

1

to the right side

\frac{2 x}{7} - \frac{1}{2} (x + 7) \geq x - 1

Multiply by LCM

4 x - 7 (x + 7) \geq 14 x - 14

Expand

- 7 (x + 7) : - 7 x - 49

4 x - 7 x - 49 \geq 14 x - 14

Add similar elements:

4 x - 7 x = - 3 x

- 3 x - 49 \geq 14 x - 14

Move

49

to the right side

- 3 x \geq 14 x + 35

Move

14 x

to the left side

- 17 x \geq 35

Multiply both sides by

- 1

17 x \leq - 35

Divide both sides by

17

x \leq - \frac{35}{17}

∣ x - 3 ∣ = 3 x + 5

\frac{45 x ^{2}}{60 x ^{2} y}

\frac{3 ^{8}}{6 ^{8}}

∣ 2 x - 5 ∣ < 5

- 5 x = - 2 x + 6

What is 1+(2x)/7-1/2 (x+7)>= x ?
The solution to 1+(2x)/7-1/2 (x+7)>= x is x<=-35/17