What is the answer to 10=(ln(2))/(ln(1+x)) ?

The answer to 10=(ln(2))/(ln(1+x)) is x=e^{(ln(2))/(10)}-1

Solve for x: 10=(ln(2))/(ln(1+x))

The solution is x=e^{(ln(2))/(10)}-1

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10 = \frac{ln ( 2 )}{ln ( 1 + x )}

x = e^{\frac{l n ( 2 )}{10}} - 1

Decimal Notation

x = 0.07177 \dots

Solution steps

10 = \frac{ln ( 2 )}{ln ( 1 + x )}

Rewrite the equation with

ln (1 + x) = u

10 = \frac{ln ( 2 )}{u}

Solve

10 = \frac{ln ( 2 )}{u} : u = \frac{ln ( 2 )}{10}

u = \frac{ln ( 2 )}{10}

Substitute back

u = ln (1 + x),

solve for

x

Solve

ln (1 + x) = \frac{ln ( 2 )}{10} : x = e^{\frac{l n ( 2 )}{10}} - 1

x = e^{\frac{l n ( 2 )}{10}} - 1

Verify Solutions:

x = e^{\frac{l n ( 2 )}{10}} - 1

True

The solution is

x = e^{\frac{l n ( 2 )}{10}} - 1

ln (x) = 7, ln (\frac{x}{e})

3 ln (x) = ln (x^{3})

lo g_{10} (x) = - 1.9

lo g_{10} (x) = - 1.4

ln (x) + ln (5 x) = 4

What is the answer to 10=(ln(2))/(ln(1+x)) ?
The answer to 10=(ln(2))/(ln(1+x)) is x=e^{(ln(2))/(10)}-1
Solve for x: 10=(ln(2))/(ln(1+x))
The solution is x=e^{(ln(2))/(10)}-1