What is the answer to log_{3}(x^2+4x+12)=2 ?

The answer to log_{3}(x^2+4x+12)=2 is x=-1,x=-3

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log_{3}(x^2+4x+12)=2

lo g_{3} (x^{2} + 4 x + 12) = 2

x = - 1, x = - 3

Solution steps

lo g_{3} (x^{2} + 4 x + 12) = 2

Apply log rules

x^{2} + 4 x + 12 = 9

Solve

x^{2} + 4 x + 12 = 9 : x = - 1, x = - 3

x = - 1, x = - 3

lo g_{2} (x) + lo g_{2} (x) = 4

ln (4 x) + ln (8 x) = 1

P, lo g_{- 1} (P) = n

lo g_{729} (x) = - \frac{5}{6}

lo g_{2} (x + 2) - 4 = - lo g_{2} (x - 4)

What is the answer to log_{3}(x^2+4x+12)=2 ?
The answer to log_{3}(x^2+4x+12)=2 is x=-1,x=-3
Solve for x: log_{3}(x^2+4x+12)=2
The solution is x=-1,x=-3