What is the answer to log_{2}(2p+1)=log_{2}(5p-2) ?

The answer to log_{2}(2p+1)=log_{2}(5p-2) is p=1

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log_{2}(2p+1)=log_{2}(5p-2)

lo g_{2} (2 p + 1) = lo g_{2} (5 p - 2)

p = 1

Solution steps

lo g_{2} (2 p + 1) = lo g_{2} (5 p - 2)

Apply log rules

2 p + 1 = 5 p - 2

Solve

2 p + 1 = 5 p - 2 : p = 1

p = 1

Verify Solutions:

p = 1

True

The solution is

p = 1

ln (x^{2}) - ln (x) - ln (4) = 0

lo g_{20} (x) + lo g_{20} (x - 1) = 1

lo g_{10} (10 x) = 3.22

lo g_{10} (x) = - 4.703389

lo g_{10} (x^{2}) = lo g_{10} (25)

What is the answer to log_{2}(2p+1)=log_{2}(5p-2) ?
The answer to log_{2}(2p+1)=log_{2}(5p-2) is p=1
Solve for p: log_{2}(2p+1)=log_{2}(5p-2)
The solution is p=1