What is the answer to log_{3}(-x-1)-log_{3}(5x)=-3 ?

The answer to log_{3}(-x-1)-log_{3}(5x)=-3 is No Solution for x\in\mathbb{R}

Solve for x: log_{3}(-x-1)-log_{3}(5x)=-3

The solution is No Solution for x\in\mathbb{R}

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lo g_{3} (- x - 1) - lo g_{3} (5 x) = - 3

No Solution for x \in R

Solution steps

lo g_{3} (- x - 1) - lo g_{3} (5 x) = - 3

Add

lo g_{3} (5 x)

to both sides

lo g_{3} (- x - 1) - lo g_{3} (5 x) + lo g_{3} (5 x) = - 3 + lo g_{3} (5 x)

Simplify

lo g_{3} (- x - 1) = - 3 + lo g_{3} (5 x)

Apply log rules

(- x - 1) \cdot 27 = 5 x

Solve

(- x - 1) \cdot 27 = 5 x : x = - \frac{27}{32}

x = - \frac{27}{32}

Verify Solutions:

x = - \frac{27}{32}

False

The solution is

No Solution for x \in R

15 = 10 lo g_{10} (S)

ln (x^{2}) = 1.3

lo g_{6} (x) + lo g_{6} (x + 5) = 10

lo g_{2 x} (27) = 3

lo g_{x} (9) = \frac{3}{2}

What is the answer to log_{3}(-x-1)-log_{3}(5x)=-3 ?
The answer to log_{3}(-x-1)-log_{3}(5x)=-3 is No Solution for x\in\mathbb{R}
Solve for x: log_{3}(-x-1)-log_{3}(5x)=-3
The solution is No Solution for x\in\mathbb{R}