What is the answer to log_{2}(2x+1)-log_{2}(x+2)=3 ?

The answer to log_{2}(2x+1)-log_{2}(x+2)=3 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(2x+1)-log_{2}(x+2)=3

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (2 x + 1) - lo g_{2} (x + 2) = 3

No Solution for x \in R

Solution steps

lo g_{2} (2 x + 1) - lo g_{2} (x + 2) = 3

Add

lo g_{2} (x + 2)

to both sides

lo g_{2} (2 x + 1) - lo g_{2} (x + 2) + lo g_{2} (x + 2) = 3 + lo g_{2} (x + 2)

Simplify

lo g_{2} (2 x + 1) = 3 + lo g_{2} (x + 2)

Apply log rules

2 x + 1 = 8 (x + 2)

Solve

2 x + 1 = 8 (x + 2) : x = - \frac{5}{2}

x = - \frac{5}{2}

Verify Solutions:

x = - \frac{5}{2}

False

The solution is

No Solution for x \in R

2 lo g_{3} (x) = lo g_{3} (16)

lo g_{x} (3) = \frac{3}{2}

x, lo g_{10} (x) = ln (y)

ln (2 x) = 14

lo g_{4} (a) - 5 + 6 lo g_{a} (4) = 0

What is the answer to log_{2}(2x+1)-log_{2}(x+2)=3 ?
The answer to log_{2}(2x+1)-log_{2}(x+2)=3 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(2x+1)-log_{2}(x+2)=3
The solution is No Solution for x\in\mathbb{R}