What is the answer to -log_{10}(x)=2.8 ?

The answer to -log_{10}(x)=2.8 is x= 1/(10^{2.8)}

Solve for x: -log_{10}(x)=2.8

The solution is x= 1/(10^{2.8)}

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- lo g_{10} (x) = 2.8

x = \frac{1}{1 0 ^{2.8}}

Decimal Notation

x = 0.00158 \dots

Solution steps

- lo g_{10} (x) = 2.8

Divide both sides by

- 1

lo g_{10} (x) = - 2.8

Apply log rules

x = \frac{1}{1 0 ^{2.8}}

Verify Solutions:

x = \frac{1}{1 0 ^{2.8}}

True

The solution is

x = \frac{1}{1 0 ^{2.8}}

- lo g_{10} (x) = 2.1

ln (5 - 2 x) = - 7

ln (5 - 2 x) = - 5

\frac{1}{x} = e^{l n (x)}

10 = \frac{50}{ln ( q + 1 )}

What is the answer to -log_{10}(x)=2.8 ?
The answer to -log_{10}(x)=2.8 is x= 1/(10^{2.8)}
Solve for x: -log_{10}(x)=2.8
The solution is x= 1/(10^{2.8)}