What is the answer to log_{7}(x+4)-log_{7}(x)=3 ?

The answer to log_{7}(x+4)-log_{7}(x)=3 is x= 2/171

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log_{7}(x+4)-log_{7}(x)=3

lo g_{7} (x + 4) - lo g_{7} (x) = 3

x = \frac{2}{171}

Decimal Notation

x = 0.01169 \dots

Solution steps

lo g_{7} (x + 4) - lo g_{7} (x) = 3

Add

lo g_{7} (x)

to both sides

lo g_{7} (x + 4) - lo g_{7} (x) + lo g_{7} (x) = 3 + lo g_{7} (x)

Simplify

lo g_{7} (x + 4) = 3 + lo g_{7} (x)

Apply log rules

x + 4 = 343 x

Solve

x + 4 = 343 x : x = \frac{2}{171}

x = \frac{2}{171}

Verify Solutions:

x = \frac{2}{171}

True

The solution is

x = \frac{2}{171}

lo g_{2} ((r + 10)^{2}) = 4

lo g_{2} (x - 6) = 5

lo g_{2} ((r + 6)^{2}) = 6

lo g_{64} (x) = \frac{3}{2}

a = \frac{1}{2 a ln ( x )}

What is the answer to log_{7}(x+4)-log_{7}(x)=3 ?
The answer to log_{7}(x+4)-log_{7}(x)=3 is x= 2/171
Solve for x: log_{7}(x+4)-log_{7}(x)=3
The solution is x= 2/171