What are the solutions to the equation 14x^2+9x+10=0 ?

The solutions to the equation 14x^2+9x+10=0 are x=-9/28+i(sqrt(479))/(28),x=-9/28-i(sqrt(479))/(28)

Find the zeros of 14x^2+9x+10=0

The zeros of 14x^2+9x+10=0 are x=-9/28+i(sqrt(479))/(28),x=-9/28-i(sqrt(479))/(28)

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14 x^{2} + 9 x + 10 = 0

x = - \frac{9}{28} + i \frac{479}{28}, x = - \frac{9}{28} - i \frac{479}{28}

Solution steps

14 x^{2} + 9 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 14 \cdot 10}{2 \cdot 14}

Simplify

9^{2} - 4 \cdot 14 \cdot 10 : 479 i

x_{1, 2} = \frac{- 9 \pm 479 i}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- 9 + 479 i}{2 \cdot 14}, x_{2} = \frac{- 9 - 479 i}{2 \cdot 14}

x = \frac{- 9 + 479 i}{2 \cdot 14} : - \frac{9}{28} + i \frac{479}{28}

x = \frac{- 9 - 479 i}{2 \cdot 14} : - \frac{9}{28} - i \frac{479}{28}

The solutions to the quadratic equation are:

x = - \frac{9}{28} + i \frac{479}{28}, x = - \frac{9}{28} - i \frac{479}{28}

x (y - z) - z (x - y) - y (x - z)

12 + 13 m + m^{2}

w^{2} - 25

2 x^{2} + 5 x - 3 = 9

0 = 12 x^{2} - 24 x

What are the solutions to the equation 14x^2+9x+10=0 ?
The solutions to the equation 14x^2+9x+10=0 are x=-9/28+i(sqrt(479))/(28),x=-9/28-i(sqrt(479))/(28)
Find the zeros of 14x^2+9x+10=0
The zeros of 14x^2+9x+10=0 are x=-9/28+i(sqrt(479))/(28),x=-9/28-i(sqrt(479))/(28)