What is the answer to log_{10}(sqrt(x^2+48x))=1 ?

The answer to log_{10}(sqrt(x^2+48x))=1 is x=2,x=-50

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log_{10}(sqrt(x^2+48x))=1

lo g_{10} (x^{2} + 48 x) = 1

x = 2, x = - 50

Solution steps

lo g_{10} (x^{2} + 48 x) = 1

Apply log rules

x^{2} + 48 x = 10

Solve

x^{2} + 48 x = 10 : x = 2, x = - 50

x = 2, x = - 50

ln (x - 1) + ln (x) = 1

ln (C) = 0

ln (x) = ln (x + 6) - ln (2)

ln (x) = - 8

x, f y = lo g_{9} (x)

What is the answer to log_{10}(sqrt(x^2+48x))=1 ?
The answer to log_{10}(sqrt(x^2+48x))=1 is x=2,x=-50
Solve for x: log_{10}(sqrt(x^2+48x))=1
The solution is x=2,x=-50