What is the answer to log_{10}(x)+log_{10}(x-8)=2 ?

The answer to log_{10}(x)+log_{10}(x-8)=2 is x=2(2+sqrt(29))

Solve for x: log_{10}(x)+log_{10}(x-8)=2

The solution is x=2(2+sqrt(29))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (x) + lo g_{10} (x - 8) = 2

x = 2 (2 + 29)

Decimal Notation

x = 14.77032 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x - 8) = 2

Apply log rules

x (x - 8) = 100

Solve

x (x - 8) = 100 : x = 2 (2 + 29), x = 2 (2 - 29)

x = 2 (2 + 29), x = 2 (2 - 29)

Verify Solutions:

x = 2 (2 + 29)

True

, x = 2 (2 - 29)

False

The solution is

x = 2 (2 + 29)

- lo g_{10} (x) = 7.8

lo g_{6} (x + 7) + lo g_{6} (x + 2) = 2

lo g_{10} (x) = 23.8

lo g_{2} (4 - 2^{x}) = 0

lo g_{3} (x) + 2 lo g_{3} (x - 6) = 4

What is the answer to log_{10}(x)+log_{10}(x-8)=2 ?
The answer to log_{10}(x)+log_{10}(x-8)=2 is x=2(2+sqrt(29))
Solve for x: log_{10}(x)+log_{10}(x-8)=2
The solution is x=2(2+sqrt(29))