What is the answer to log_{10}(x2+4x-18)=2x-5 ?

The answer to log_{10}(x2+4x-18)=2x-5 is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(x2+4x-18)=2x-5

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (x 2 + 4 x - 18) = 2 x - 5

No Solution for x \in R

Solution steps

lo g_{10} (x \cdot 2 + 4 x - 18) = 2 x - 5

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x \cdot 2 + 4 x - 18)} = 1 0^{2 x - 5}

Simplify

1 0^{l o g_{10} (x \cdot 2 + 4 x - 18)} : 6 x - 18

6 x - 18 = 1 0^{2 x - 5}

Solve

6 x - 18 = 1 0^{2 x - 5} :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (2^{x}) = x lo g_{10} (2)

6 = 10 lo g_{10} (x)

lo g_{2} (x) + lo g_{2} (5) = 2

2 ln (x) = ln (5 x + 14)

8.4 = - lo g_{10} (x)

What is the answer to log_{10}(x2+4x-18)=2x-5 ?
The answer to log_{10}(x2+4x-18)=2x-5 is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(x2+4x-18)=2x-5
The solution is No Solution for x\in\mathbb{R}