What is the answer to log_{4}(x)+log_{4}(x+12)=3 ?

The answer to log_{4}(x)+log_{4}(x+12)=3 is x=4

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log_{4}(x)+log_{4}(x+12)=3

lo g_{4} (x) + lo g_{4} (x + 12) = 3

x = 4

Solution steps

lo g_{4} (x) + lo g_{4} (x + 12) = 3

Apply log rules

x (x + 12) = 64

Solve

x (x + 12) = 64 : x = 4, x = - 16

x = 4, x = - 16

Verify Solutions:

x = 4

True

, x = - 16

False

The solution is

x = 4

3 ln (x) = ln (3 x)

\frac{9}{5} lo g_{4} (x) = - 8

lo g_{5} (2 x + 1) = 1 - lo g_{5} (x + 2)

ln (y) = x + ln (x), y

lo g_{5} (x + 4) + lo g_{5} (x + 1) = 1

What is the answer to log_{4}(x)+log_{4}(x+12)=3 ?
The answer to log_{4}(x)+log_{4}(x+12)=3 is x=4
Solve for x: log_{4}(x)+log_{4}(x+12)=3
The solution is x=4