What are the solutions to the equation 2x^2+24=0 ?

The solutions to the equation 2x^2+24=0 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of 2x^2+24=0

The zeros of 2x^2+24=0 are x=2sqrt(3)i,x=-2sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 24 = 0

x = 23 i, x = - 23 i

Solution steps

2 x^{2} + 24 = 0

Move

24

to the right side

2 x^{2} = - 24

Divide both sides by

2

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

25 - 36 d^{2}

4 n - 6 < 10 n + 7

7 + (- 3)

x^{6} y^{4} - y^{7}

x^{8} - 25 x^{5} - 54 x^{2}

What are the solutions to the equation 2x^2+24=0 ?
The solutions to the equation 2x^2+24=0 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of 2x^2+24=0
The zeros of 2x^2+24=0 are x=2sqrt(3)i,x=-2sqrt(3)i