What is the answer to log_{2}((r+7)^2)=4 ?

The answer to log_{2}((r+7)^2)=4 is r=-3,r=-11

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log_{2}((r+7)^2)=4

lo g_{2} ((r + 7)^{2}) = 4

r = - 3, r = - 11

Solution steps

lo g_{2} ((r + 7)^{2}) = 4

Apply log rules

(r + 7)^{2} = 16

Solve

(r + 7)^{2} = 16 : r = - 3, r = - 11

r = - 3, r = - 11

lo g_{3} ((r + 16)^{2}) = 4

x, lo g_{10} (x) = - 1.5

2.5 x^{2} = 5 x lo g_{2} (x) 4

lo g_{3} (x^{2} - x - 4) = 2

lo g_{4} (x) - 4 lo g_{x} (4) + 3 = 0

What is the answer to log_{2}((r+7)^2)=4 ?
The answer to log_{2}((r+7)^2)=4 is r=-3,r=-11
Solve for r: log_{2}((r+7)^2)=4
The solution is r=-3,r=-11