What is the answer to log_{4}(x+8)+log_{4}(x+2)=2 ?

The answer to log_{4}(x+8)+log_{4}(x+2)=2 is x=0

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log_{4}(x+8)+log_{4}(x+2)=2

lo g_{4} (x + 8) + lo g_{4} (x + 2) = 2

x = 0

Solution steps

lo g_{4} (x + 8) + lo g_{4} (x + 2) = 2

Apply log rules

(x + 8) (x + 2) = 16

Solve

(x + 8) (x + 2) = 16 : x = 0, x = - 10

x = 0, x = - 10

Verify Solutions:

x = 0

True

, x = - 10

False

The solution is

x = 0

lo g_{e} (x) + lo g_{e} (7 x + 1) = 1

ln (8^{x^{2}}) = ln (9^{x})

4 ln (x) = 2 ln (16)

lo g_{x} (243) = \frac{5}{3}

lo g_{2} (2 + lo g_{3} (x - 2)) = 2

What is the answer to log_{4}(x+8)+log_{4}(x+2)=2 ?
The answer to log_{4}(x+8)+log_{4}(x+2)=2 is x=0
Solve for x: log_{4}(x+8)+log_{4}(x+2)=2
The solution is x=0