What are the solutions to the equation a^2+18=9a ?

The solutions to the equation a^2+18=9a are a=6,a=3

Find the zeros of a^2+18=9a

The zeros of a^2+18=9a are a=6,a=3

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a^{2} + 18 = 9 a

a = 6, a = 3

Solution steps

a^{2} + 18 = 9 a

Move

9 a

to the left side

a^{2} + 18 - 9 a = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 9 a + 18 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

a_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

a = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

a = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

a = 6, a = 3

\frac{x}{y} d x

∣ 8 - 2 x ∣ \leq 18

2 (\frac{1}{3})^{- 2}

∣ 4 y - 1 ∣ \geq 6

- 1 \leq - 2

What are the solutions to the equation a^2+18=9a ?
The solutions to the equation a^2+18=9a are a=6,a=3
Find the zeros of a^2+18=9a
The zeros of a^2+18=9a are a=6,a=3