What is the answer to log_{4}(x+12)+log_{4}(x)=3 ?

The answer to log_{4}(x+12)+log_{4}(x)=3 is x=4

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log_{4}(x+12)+log_{4}(x)=3

lo g_{4} (x + 12) + lo g_{4} (x) = 3

x = 4

Solution steps

lo g_{4} (x + 12) + lo g_{4} (x) = 3

Apply log rules

(x + 12) x = 64

Solve

(x + 12) x = 64 : x = 4, x = - 16

x = 4, x = - 16

Verify Solutions:

x = 4

True

, x = - 16

False

The solution is

x = 4

8 lo g_{2} (x + 1) = 40

ln (x) + ln (x - 5) = ln (7 x)

ln (x + 3) + 2 ln (3) = ln (5)

lo g_{10} (x^{2}) - 2 = 0

lo g_{10} (x) = 19.09

What is the answer to log_{4}(x+12)+log_{4}(x)=3 ?
The answer to log_{4}(x+12)+log_{4}(x)=3 is x=4
Solve for x: log_{4}(x+12)+log_{4}(x)=3
The solution is x=4