What is the answer to log_{2}(x)= 1/x ?

The answer to log_{2}(x)= 1/x is x=(ln(2))/(\W_{0)(ln(2))}

Solve for x: log_{2}(x)= 1/x

The solution is x=(ln(2))/(\W_{0)(ln(2))}

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lo g_{2} (x) = \frac{1}{x}

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

Decimal Notation

x = 1.55961 \dots

Solution steps

lo g_{2} (x) = \frac{1}{x}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (x)} = 2^{\frac{1}{x}}

Simplify

2^{l o g_{2} (x)} : x

x = 2^{\frac{1}{x}}

Solve

x = 2^{\frac{1}{x}} : x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

Verify Solutions:

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

True

The solution is

x = \frac{ln ( 2 )}{W _{0} ( ln ( 2 ) )}

lo g_{x + 3} (9) = 3

j (x) = \frac{x}{ln ( x )}

- lo g_{10} (x) = 0.05

lo g_{\frac{3}{4}} (x) = - 2

ln (3 x) = ln (4 x + 1) + ln (1 - x)

What is the answer to log_{2}(x)= 1/x ?
The answer to log_{2}(x)= 1/x is x=(ln(2))/(\W_{0)(ln(2))}
Solve for x: log_{2}(x)= 1/x
The solution is x=(ln(2))/(\W_{0)(ln(2))}