What is the answer to solvefor m,log_{m}(4)=d ?

The answer to solvefor m,log_{m}(4)=d is m=4^{1/d} {d 0}

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solvefor m,log_{m}(4)=d

solve for

m, lo g_{m} (4) = d

m = 4^{\frac{1}{d}} {d < 0 or d > 0}

Solution steps

lo g_{m} (4) = d

Apply log rules

\frac{1}{lo g _{4} ( m )} = d

Multiply both sides by

lo g_{4} (m)

\frac{1}{lo g _{4} ( m )} lo g_{4} (m) = d lo g_{4} (m)

Simplify

1 = d lo g_{4} (m)

Switch sides

d lo g_{4} (m) = 1

Divide both sides by

d

lo g_{4} (m) = \frac{1}{d}

Apply log rules

m = 4^{\frac{1}{d}}

Verify Solutions:

m = 4^{\frac{1}{d}} {d < 0 or d > 0}

The solution is

m = 4^{\frac{1}{d}} {d < 0 or d > 0}

lo g_{7} (81) = 4 lo g_{7} (x)

lo g_{x} (\frac{1}{3}) = 10

0.78 = ln (y)

lo g_{7} (8) = 3 lo g_{7} (x)

x, t = lo g_{10} (x)

What is the answer to solvefor m,log_{m}(4)=d ?
The answer to solvefor m,log_{m}(4)=d is m=4^{1/d} {d<0\lor d>0}