What is the answer to log_{5}(x+1)=log_{5}(2+2x) ?

The answer to log_{5}(x+1)=log_{5}(2+2x) is No Solution for x\in\mathbb{R}

Solve for x: log_{5}(x+1)=log_{5}(2+2x)

The solution is No Solution for x\in\mathbb{R}

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lo g_{5} (x + 1) = lo g_{5} (2 + 2 x)

No Solution for x \in R

Solution steps

lo g_{5} (x + 1) = lo g_{5} (2 + 2 x)

Apply log rules

x + 1 = 2 + 2 x

Solve

x + 1 = 2 + 2 x : x = - 1

x = - 1

Verify Solutions:

x = - 1

False

The solution is

No Solution for x \in R

lo g_{3} (x) + lo g_{9} (x) = 3

lo g_{10} (n) = 1 0^{10}

lo g_{b} (2) = 2.55

lo g_{3} (x + 4) + lo g_{3} (x + 4) = 2

lo g_{2 x} (2 x^{2} + 8 x - 6) = 2

What is the answer to log_{5}(x+1)=log_{5}(2+2x) ?
The answer to log_{5}(x+1)=log_{5}(2+2x) is No Solution for x\in\mathbb{R}
Solve for x: log_{5}(x+1)=log_{5}(2+2x)
The solution is No Solution for x\in\mathbb{R}