What is the answer to ln(x)+ln(x-2)-ln(x+4)=0 ?

The answer to ln(x)+ln(x-2)-ln(x+4)=0 is x=4

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ln(x)+ln(x-2)-ln(x+4)=0

ln (x) + ln (x - 2) - ln (x + 4) = 0

x = 4

Solution steps

ln (x) + ln (x - 2) - ln (x + 4) = 0

Apply log rules

x (x - 2) = x + 4

Solve

x (x - 2) = x + 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

False

The solution is

x = 4

8 = ln (x)

- x = ln (2 x)

lo g_{3} (x + 4) = - 3

x, ln (x^{2} - y^{2}) = 0

x, ln (y) = 2 ln (x) + C

What is the answer to ln(x)+ln(x-2)-ln(x+4)=0 ?
The answer to ln(x)+ln(x-2)-ln(x+4)=0 is x=4
Solve for x: ln(x)+ln(x-2)-ln(x+4)=0
The solution is x=4