What is the answer to log_{2}(x)-log_{2}(x+3)=-21 ?

The answer to log_{2}(x)-log_{2}(x+3)=-21 is x= 3/2097151

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log_{2}(x)-log_{2}(x+3)=-21

lo g_{2} (x) - lo g_{2} (x + 3) = - 21

x = \frac{3}{2097151}

Decimal Notation

x = 1.43051 E - 6

Solution steps

lo g_{2} (x) - lo g_{2} (x + 3) = - 21

Add

lo g_{2} (x + 3)

to both sides

lo g_{2} (x) - lo g_{2} (x + 3) + lo g_{2} (x + 3) = - 21 + lo g_{2} (x + 3)

Simplify

lo g_{2} (x) = - 21 + lo g_{2} (x + 3)

Apply log rules

x \cdot 2097152 = x + 3

Solve

x \cdot 2097152 = x + 3 : x = \frac{3}{2097151}

x = \frac{3}{2097151}

Verify Solutions:

x = \frac{3}{2097151}

True

The solution is

x = \frac{3}{2097151}

(0.025 \cdot ln (1 + x)) = 0.22

lo g_{2} (2 \cdot x) = 4

5 lo g_{6} (7 w + 1) + 3 = 13

0.73 = ln (y)

lo g_{3} (x^{2} + 5) = 2

What is the answer to log_{2}(x)-log_{2}(x+3)=-21 ?
The answer to log_{2}(x)-log_{2}(x+3)=-21 is x= 3/2097151
Solve for x: log_{2}(x)-log_{2}(x+3)=-21
The solution is x= 3/2097151