What is the answer to solvefor x,ln(y)=ln(x^x) ?

The answer to solvefor x,ln(y)=ln(x^x) is x=(ln(y))/(\W(ln(y)))

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solvefor x,ln(y)=ln(x^x)

solve for

x, ln (y) = ln (x^{x})

x = \frac{ln ( y )}{W ( ln ( y ) )}

Solution steps

ln (y) = ln (x^{x})

Apply log rules

y = x^{x}

Solve

y = x^{x} : x = \frac{ln ( y )}{W ( ln ( y ) )}

x = \frac{ln ( y )}{W ( ln ( y ) )}

Verify Solutions:

x = \frac{ln ( y )}{W ( ln ( y ) )}

True

The solution is

x = \frac{ln ( y )}{W ( ln ( y ) )}

- 8 lo g_{9} (n) = 16

x, lo g_{10} (x) + 4 = 104

6 ln (3 x + 6) + 14 = 2

ln (x) = ln (3) + ln (x - 5)

ln (x) = 3.941977858

What is the answer to solvefor x,ln(y)=ln(x^x) ?
The answer to solvefor x,ln(y)=ln(x^x) is x=(ln(y))/(\W(ln(y)))