What is the answer to log_{4}(2x-6)=log_{4}(4^2) ?

The answer to log_{4}(2x-6)=log_{4}(4^2) is x=11

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log_{4}(2x-6)=log_{4}(4^2)

lo g_{4} (2 x - 6) = lo g_{4} (4^{2})

x = 11

Solution steps

lo g_{4} (2 x - 6) = lo g_{4} (4^{2})

Apply log rules

2 x - 6 = 16

Solve

2 x - 6 = 16 : x = 11

x = 11

Verify Solutions:

x = 11

True

The solution is

x = 11

lo g_{6} (x^{2} - 28) = 2

ln (x) = c (ln (4))^{2}

- ln (4 - z^{2}) + c = 0

x = lo g_{10} (3 (5^{x}))

lo g_{3} (x + 3) - lo g_{3} (3 - x) = 3

What is the answer to log_{4}(2x-6)=log_{4}(4^2) ?
The answer to log_{4}(2x-6)=log_{4}(4^2) is x=11
Solve for x: log_{4}(2x-6)=log_{4}(4^2)
The solution is x=11