What is the answer to log_{2}(4x+1)=5 ?

The answer to log_{2}(4x+1)=5 is x= 31/4

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log_{2}(4x+1)=5

lo g_{2} (4 x + 1) = 5

x = \frac{31}{4}

Decimal Notation

x = 7.75

Solution steps

lo g_{2} (4 x + 1) = 5

Apply log rules

4 x + 1 = 32

Solve

4 x + 1 = 32 : x = \frac{31}{4}

x = \frac{31}{4}

y, x = lo g_{2} (5 y)

lo g_{5} (4 x + 5) = 4

lo g_{3} ((x^{2} + 2)^{2}) = 6

- 2 ln (x + 4) = 0

e^{2 l n (x)} = 4 x + 21

What is the answer to log_{2}(4x+1)=5 ?
The answer to log_{2}(4x+1)=5 is x= 31/4
Solve for x: log_{2}(4x+1)=5
The solution is x= 31/4